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3 years ago

HELP WITH 4,5 and 6 PLEASE !!!!

Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

All you do for #4 and # 5 is plug the x values FROM THE TABLE into the equation, and see if you get the y values listed in the table. You don't, so you can see that the equations DO NOT REPRESENT THE DATA IN THE TABLE. For #6 you can see from the graph that one point on the line is (1,-2) which does represent the table of values. Looking further, as each x value decreases by 1, the y value decreases by 3, so (0,-5) makes sense too, again supporting the idea that the graph DOES represent the table of values

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What is the difference between a radius and a diameter of a circle?

34kurt

Answer:

Radius is half of the diameter.

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4 years ago

PLEASE HELP I DO NOT UNDERSTAND AT ALL AND SHOW YOUR WORK !!

Agata [3.3K]

Answer:

y intercept (-6,0), x-intercept (0,-8) : $y = \frac{-4}{3}x -8$

y intercept (0,-6), x-intercept (-2,0): $y = -3x -6$

y intercept (0,8), x-intercept (1.6,0): $y = -5x + 8$

y intercept (0,7), x-intercept (-1.4,0): $y = 5x + 7$

Step-by-step explanation:

y = mx + b

*note: b is the y intercept

1. y intercept (-6,0), x-intercept (0,-8)

$m = \frac{-8 - 0}{0 - (-6)}= \frac{-8}{6} = \frac{-4}{3}\\y = \frac{-4}{3}x + b\\y = \frac{-4}{3}x -8$

2.y intercept (0,-6), x-intercept (-2,0)

$m = \frac{0 - (-6)}{-2 - 0} = \frac{6}{-2} = -3\\y = -3x + b \\y = -3x -6$

3. y intercept (0,8), x-intercept (1.6,0)

$m = \frac{0 - 8}{1.6 - 0}= \frac{-8}{1.6} = -5\\y = -5x + b\\y = -5x + 8$

4. y intercept (0,7), x-intercept (-1.4,0)

$m = \frac{0 - 7}{-1.4 - 0} = \frac{-7}{-1.4}= 5 \\y = 5x + b\\y = 5x + 7$

6 0

3 years ago

− 8/7 +(−1/2) reduced to simplest form

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Answer:

simplified would be -23/14 if you wanted to answer this it would be either -1 9/14 or -1.64

Step-by-step explanation:

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3 years ago

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To find the answer to this problem, you would multiply 4/5 to 12 (or 12/1). And you would end up with 48/5, and when you divide this out, you would end up with 9.6. So 9.6 should be your final answer.
Hope this helped! :)

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3 years ago

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