Given that an insurance policy reimburses a loss with a deductible of 5. That is, if a loss is less than 5, policy will pay zero. If it is more than 5, then the policy will pay (loss - 5).

We have distribution of y as

$f(y) = \frac{2}{y^3} , y>1\\ =0 otherwise$

expected value of the benefit paid under the insurance policy

= $E(Y-5)\\=E(Y)-5$ , by linearity property of expectation.

$E(y) = \int\limits^\infty_1 {y(\frac{2}{y^3} )} \, dy\\=\frac{-2}{y} \\=-0+2\\=2$

Hence expected value of the benefit paid under the insurance policy

=2-5 =-3

8 0

4 years ago

School fundraiser Amy sold 28 bags of popcorn and 40 candy bars and made to 282. Sarah sold 17 bags of popcorn 20 candy bars and

aev [14]

Answer:

cost of popcorn bag is 6.5

Step-by-step explanation:

Here, we want to find the cost of a popcorn bag

let the cost of a bag of popcorn be p

let the cost of a bag of candy bar be c

Mathematically;

28p + 40c = 282

17p + 20c = 160.50

Multiply ii by 2 and subtract from i

28p + 40c = 282

34p + 40c = 321

34p-28p = 321-282

6p = 39

p = 39/6

p = 6.5

6 0

3 years ago

HURRY!!!! Thank you!

serious [3.7K]

Answer:

Step-by-step explanation:

Hope this helps

7 0

3 years ago