3 years ago

Solve the inequality 8(u + 8) ≥ 8u+8

Mathematics

1 answer:

Luden [163]3 years ago

7 0

Two solutions were found :

u ≥ 2
u ≤ 0

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Read 2 more answers

Select the correct answer.

Sonja [21]

Answer:

B) 5 + 17i is your answer.

Step-by-step explanation:

In order to write this equation as a complex number in standard form, you must first simplify each term.

Apple the distributive property.

21 - 4i - 1 * 16 - (7i) + 28i

Multiply -1 by 16.

21 - 4i -16 - (7i) + 28i

Multiply 7 by -1.

21 - 4i - 16 - 7i + 28i

Now simplify by adding terms :)

Subtract 16 from 21.

5 - 4i - 7i + 28i

Subtract 7i from -4i.

5 - 11i + 28i

Add -11i and 28i.

= 5 + 17i

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Please answer this correctly

Paraphin [41]

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3 years ago

Standard equation of circle with center of (6,8) that passes through point (-1,4)

dezoksy [38]

Answer:

The result should be:

$(x-6)^2+(y-8)^2=\sqrt{65}$

Step-by-step explanation:

-The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$ where the center is $(h,k)$ , the point $(x,y)$ and the radius known as $r$ .

-Use the center (6,8) and the point (-1,4) for this equation:

$(-1-6)^2+(4-8)^2=r^2$

-Then, you solve for the radius and get the equation:

$(-1-6)^2+(4-8)^2=r^2$

$(-7)^2+(-4)^2 =r^2$

$49 + 16 = r^2$

$65 = r^2$

$\sqrt{65} =\sqrt{r^2}$

$\sqrt{65} = r$

-Result:

$(x-6)^2+(y-8)^2=\sqrt{65}$

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Step-by-step explanation:

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