Question

SOMEONE HELP ME ASAP PLZZ!!!

Answer 1

Answer:

The distance of the plane from the base of the tower is 25.5 foot.

Step-by-step explanation:

As given

Max is in a control tower at a small airport.

He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.

Now by using the trigonometric identity.

$tan\theta = \frac{Perpendicular}{Base}$

As shown in the figure given below

Perpendicular = CB

Base = AC = 50 feet

$\theta = 27^{\circ}$

Put in the identity.

$tan\ 27^{\circ} = \frac{CB}{AC}$

$tan\ 27^{\circ} = \frac{CB}{50}$

$tan\ 27^{\circ} = 0.51\ (Approx)$

Put in the above

$0.51 = \frac{CB}{50}$

CB = 0.51 × 50

CB = 25.5 foot

Therefore the distance of the plane from the base of the tower is 25.5 foot.