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daser333 [38]
3 years ago
10

Some residuals for a scatterplot are given. for x = 3, the residual is –5. for x = 5, the residual is –1. for x = 7, the residua

l is 3. for x = 9, the residual is 0. for which value of x is the data point farthest from the line of best fit? 3 5 7 9
Mathematics
1 answer:
Viktor [21]3 years ago
7 0

The value of x that is the data point farthest from the line of best fit is 3

<h3>How to determine the x value farthest from the line of best fit?</h3>

The given parameters are:-

x      Residual

3         -5

5         -1

7          3

9          0

Take the absolute value of the residuals

x      Residual

3         5

5         1

7         3

9         0

The largest absolute value is 5

Hence, the value of x that is the data point farthest from the line of best fit is 3

Read more about residuals at:

brainly.com/question/16180255

#SPJ4

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3 years ago
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The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
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I don't understand this question but the company I choose was PepsiCo. The shares price is $146.02​
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9514 1404 393

Answer:

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Step-by-step explanation:

At a cost of $146.02 per share, $20,000 will buy ...

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Some accounts will let you purchase partial shares; others require you purchase whole shares. $20,000 is enough to pay for 136.96754 shares, but you may be able to purchase only 136 shares. (You would have $141.28 in cash remaining after that transaction.)

Some accounts manage shares in multiples of 0.001 shares; others may use more decimal places. Above, we have shown the quantity that spends the entire $20,000. Using fewer decimal places will leave some cash remaining.

We have assumed you're not paying any brokerage fees or loads that would reduce the amount of money that actually purchases shares.

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<em>Additional comment</em>

Whenever you buy anything, the cost of more than one of it is the unit price times the number of units. (Quantity discounts may apply.) In like fashion, the cost of multiple shares of stock is the single-share cost multiplied by the number of shares. As with all multiplication relations, a corresponding division relation is <em>the number of shares is the total cost divided by the cost per share</em>.

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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Greatest number to lowest number sequence:

275, 262, 26.2

6 0
3 years ago
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