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daser333 [38]
2 years ago
10

Some residuals for a scatterplot are given. for x = 3, the residual is –5. for x = 5, the residual is –1. for x = 7, the residua

l is 3. for x = 9, the residual is 0. for which value of x is the data point farthest from the line of best fit? 3 5 7 9
Mathematics
1 answer:
Viktor [21]2 years ago
7 0

The value of x that is the data point farthest from the line of best fit is 3

<h3>How to determine the x value farthest from the line of best fit?</h3>

The given parameters are:-

x      Residual

3         -5

5         -1

7          3

9          0

Take the absolute value of the residuals

x      Residual

3         5

5         1

7         3

9         0

The largest absolute value is 5

Hence, the value of x that is the data point farthest from the line of best fit is 3

Read more about residuals at:

brainly.com/question/16180255

#SPJ4

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The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

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Evaluate the combination expression

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