The type of windows I am using is:Windows 8.1
Answer:
Following is attached the code that works accordingly as required. It reads in characters from standard input and outputs the number of times it sees an 'a' followed by the letter 'b'. All the description of program is given inside the code as comments.
I hope it will help you!
Explanation:
Answer:
#include <stdio.h>
void interchangeCase(char phrase[],char c){
for(int i=0;phrase[i]!='\0';i++){
if(phrase[i]==c){
if(phrase[i]>='A' && phrase[i]<='Z')
phrase[i]+=32;
else
phrase[i]-=32;
}
}
}
int main(){
char c1[]="Eevee";
interchangeCase(c1,'e');
printf("%s\n",c1);
char c2[]="Eevee";
interchangeCase(c2,'E');
printf("%s\n",c2);
}
Explanation:
- Create a function called interchangeCase that takes the phrase and c as parameters.
- Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
- If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
- Inside the main function, test the program and display the results.
Explanation:
We can divide the multiplex in different categorize, for example:
- FREQUENCY DIVISION MULTIPLEXERS (FDM)
-
TIME DIVISION MULTIPLEXERS (TDM)
-
STATISTICAL TIME DIVISION MULTIPLEXERS (STDM).
But in this case, we're going to explain about the time and frequency, because the time division multiplex differ to frequency, because the circuit is divided horizontally, and the time is vertically
b. splits the communication circuit vertically (with time slots) instead of horizontally
Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
