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tankabanditka [31]
3 years ago
9

Integral 3t+ 1 / (t + 1)^2​

Computers and Technology
1 answer:
Verizon [17]3 years ago
5 0

Answer:

3ln|t+1|+\frac{2}{t+1} +C

Explanation:

We'll be using u-substitution for this problem.

Let

u=t+1\\du=dt

Substitute

\int\limits {\frac{3u-2}{u^2}} \, du

Split the fraction

\int\limits {\frac{3u}{u^2} } \, du -\int\limits {\frac{2}{u^2} } \, du

Move the constants out

3\int\limits {\frac{u}{u^2}du -2\int\limits {u^{-2}} \, du

Simplify

3\int\limits {\frac{1}{u}du -2\int\limits {u^{-2}} \, du

Integrate

3ln|u|+\frac{2}{u} +C

Substitute

3ln|t+1|+\frac{2}{t+1} +C

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Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   double side, height;

   

   cout<<"Enter the length of one of the sides of the base: ";

   cin>>side;

   cout<<"Enter the height: ";

   cin>>height;

   

   double area = side * side;

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   cout<<"The area of the base of the pyramid is: "<<area<<endl;

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<u>Pseudocode:</u>

Declare side, height

Get side

Get height

Set area = side * side

Set volume = area * height / 3

Print area

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Print volume

Explanation:

Include <iomanip> to have two decimal places

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Ask the user to enter side and height

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Print area, height and volume (use <em>fixed</em> and <em>setprecision(2)</em> to have two decimal places)

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Answer:

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Answer:

Explanation:

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