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tankabanditka [31]
3 years ago
9

Integral 3t+ 1 / (t + 1)^2​

Computers and Technology
1 answer:
Verizon [17]3 years ago
5 0

Answer:

3ln|t+1|+\frac{2}{t+1} +C

Explanation:

We'll be using u-substitution for this problem.

Let

u=t+1\\du=dt

Substitute

\int\limits {\frac{3u-2}{u^2}} \, du

Split the fraction

\int\limits {\frac{3u}{u^2} } \, du -\int\limits {\frac{2}{u^2} } \, du

Move the constants out

3\int\limits {\frac{u}{u^2}du -2\int\limits {u^{-2}} \, du

Simplify

3\int\limits {\frac{1}{u}du -2\int\limits {u^{-2}} \, du

Integrate

3ln|u|+\frac{2}{u} +C

Substitute

3ln|t+1|+\frac{2}{t+1} +C

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Answer:

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7 0
2 years ago
For the following array x [10] = { 45, 20, 50, 30, 80, 10, 60, 70, 40, 90} show the contents of x after the function call split
Valentin [98]

Answer:

The array index by using split function.

45 20 50 30 80 10 60 70 40 90

45 20 40 30 80 10 60 70 50 90

45 20 40 30 10 80 60 70 50 90

10 20 40 30 45 80 60 70 50 90

Explanation:

In the following statement, there is an integer array type variable x and its index value is 10 that means it contains only 10 numeric values and then, they set split function which split the array and the split function is the built-in function which is used to separate the string or an array. So, the array is split into the following parts.

5 0
3 years ago
Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print
yawa3891 [41]

Answer:

Step by step explanation along with code and output is provided below.

Explanation:

// the outer loop is for printing digits starting from 1 to numRows

// the inner loop is for printing letters starting from 'A' to numCols

//  char cols = 'A';   should not be inside inner loop or outside outer loop, in both these cases char either repeats itself or continues in a sequence. Therefore it must be inside of outer loop

//  int rows = 1;  ensures that row starts at 1

#include <iostream>

using namespace std;

int main()

{

int numRows;

int numCols;

int rows = 1;

cout <<"Enter number of Rows"<<endl;

cin>>numRows;

cout <<"Enter number of Columns"<<endl;

cin>>numCols;

cout<<"Seats in the theater are:"<<endl;

for(int i = 0; i < numRows; i++)

{

  char cols = 'A';  

 for(int j = 0; j < numCols; j++)

 {

  cout <<rows << cols << " ";

  cols= cols + 1;

 }

 rows= rows + 1;

}

  return 0;

}

Output:

When Rows = 2 and Columns = 3

Enter number of Rows

2

Enter number of Columns

3

Seats in the theater are:

1A 1B 1C 2A 2B 2C

When Rows = 4 and Columns = 5

Enter number of Rows

4

Enter number of Columns

5

Seats in the theater are:

1A 1B 1C 1D 1E 2A 2B 2C 2D 2E 3A 3B 3C 3D 3E 4A 4B 4C 4D 4E

Hence program is working correctly for any number of rows and columns

6 0
2 years ago
Question 1 of 10
ycow [4]

Answer:

Explanation:

Def f

4 0
2 years ago
Assuming dataFile is an ofstream object associated with a disk file named payroll.dat, which of the following statements would w
svet-max [94.6K]

Answer:

dataFile << salary;

Explanation:

To write salary to a file (payroll.dat) using ofstream, you make use of the following instruction:

<em>ofstream dataFile; </em>

<em>myfile.open ("payroll.dat"); </em>

<em>myfile <<salary; </em>

<em>myfile.close();</em>

<em />

This line creates an instance of ofstream

<em>ofstream dataFile; </em>

This line opens the file payroll.dat

<em>myfile.open ("payroll.dat"); </em>

This is where the exact instruction in the question is done. This writes the value of salary to payroll.dat

<em>myfile <<salary; </em>

This closes the opened file

<em>myfile.close();</em>

<em />

<em />

8 0
2 years ago
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