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tankabanditka [31]
3 years ago
9

Integral 3t+ 1 / (t + 1)^2​

Computers and Technology
1 answer:
Verizon [17]3 years ago
5 0

Answer:

3ln|t+1|+\frac{2}{t+1} +C

Explanation:

We'll be using u-substitution for this problem.

Let

u=t+1\\du=dt

Substitute

\int\limits {\frac{3u-2}{u^2}} \, du

Split the fraction

\int\limits {\frac{3u}{u^2} } \, du -\int\limits {\frac{2}{u^2} } \, du

Move the constants out

3\int\limits {\frac{u}{u^2}du -2\int\limits {u^{-2}} \, du

Simplify

3\int\limits {\frac{1}{u}du -2\int\limits {u^{-2}} \, du

Integrate

3ln|u|+\frac{2}{u} +C

Substitute

3ln|t+1|+\frac{2}{t+1} +C

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