Answer:
3 bottles
Step-by-step explanation:
Hello!
First, we find out how many fluid ounces 25 cups of juice hold.
One cup holds 12 fluid ounces so to find 25 we do
25 * 12 = 300 fluid ounces
Next, we find out how many fluid ounces one gallon holds.
One gallon is 4 quarts.
1 quart is 32 fluid ounces so to find how many 4 holds we do
32 * 4 = 128
So one gallon holds 128 fluid ounces
To find how many we need we divide the total needed by how much one bottle holds
300/128 = 2.34
You can't buy exactly 2.34 bottles of juice so we round up to the nearest whole number we will just have extra leftover
The answer is 3 bottles
Hope this helps!
The area of a 2D form is the amount of space within its perimeter. The area of the rectangle is 12 units². Thus, the correct option is A.
<h3>What is an area?</h3>
The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.
As per the given information, the graph of the rectangle can be made as shown below. It can be observed from the graph that the length of the rectangle and width of the rectangle are 4 units and 3 units, respectively. Therefore, the area of the rectangle is,
Area = 4 units × 3 units = 12 units²
Hence, the area of the rectangle is 12 units². Thus, the correct option is A.
Learn more about the Area:
brainly.com/question/1631786
#SPj1
6n > n + 20. Hope it helps!
I would be 506.110 cause if it is over five then round it to ten
Answer:
The values of a and b are:
Step-by-step explanation:
Given the exponential model

Given the points
(0, 2) and (3, 128)
We know that the y-intercept of
is (0, a).
so
a = 2
putting x = 3, y = 128 and a = 2


Switching sides



Taking the real value such as:
![\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dx%5E3%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dx%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D)
so
![b=\sqrt[3]{64}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B64%7D)
![b=\sqrt[3]{4^3}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B4%5E3%7D)

Therefore,