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leva [86]
3 years ago
9

Solve for d. d + 67 = 87 р Submit

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

d = 20

Step-by-step explanation:

Vsevolod [243]3 years ago
7 0

Answer:

d=20

Step-by-step explanation:

d+67=87

Subtract 67 from both sides

d=20

Hope this is helpful

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HELPP
Harrizon [31]

Answer:

Step-by-step explanation:

Alright, lets get started.

Lets find slope for both bikes one by one

For bike 1 :

There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)

So the slope for bike 1 is : \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

So the slope for bike 1 is : \frac{6-3}{4-2}

So the slope for bike 1 is : \frac{3}{2}

For bike 2 :

There are two points on the graph of Bike 2, these two points are (4,5) and (8,10)

So the slope for bike 2 is : \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

So the slope for bike 2 is : \frac{10-5}{8-4}=\frac{5}{4}

Hence Bike 1 will win the race as slope of line bike1 is greater than slope of line bike 2.  So, answer is option D


3 0
3 years ago
Read 2 more answers
What is 1+1 ?<br><br> Plz help!!! Hurry plz, I need to know.
DaniilM [7]

Answer:

hmmm...? im gonna guess 2

Step-by-step explanation:

i finger plus another finger gives me......ahhhhh ik the answer its 2

4 0
3 years ago
Read 2 more answers
Helpppppp mathhhhhhhhh
creativ13 [48]
I hope this helps you




cos71=15/P



0.325=15/P



P=46.15
8 0
3 years ago
The two ends of this triangular right prism are equilateral triangles. The
maria [59]

If the two ends of this triangular right prism are equilateral triangles. The surface area of the prism is 74cm.

<h3>Surface area</h3>

Using this formula

A=bh+L(S1+S2+S3)

Where:

L=5cm

b=4cm

h=3.5cm

S1=4cm

S2=4cm

S3=4cm

Let plug in the formula

A=4(3.5)+5(4+4+4)

A=14+5(12)

A=14+60

A=74 cm

Therefore the surface area of the prism is 74cm.

Learn more about surface area here:brainly.com/question/16519513

#SPJ1

7 0
2 years ago
In the solution to this system, what is the value of y? x+y+z=1x+y+z=1 2x+y−z=82x+y-z=8 x−y+z=−5
kirza4 [7]
If you have multiple equations with multiple variables, you can either do clever substitutions, or turn it into a matrix on which you can perform linear combinations or multiplications (Gauss elimination)

1  1   1  1
2  1  -1  8
1 -1   1  -5

(note how the above 3 rows represent the 3 equations, just got rid of the variables, plus sign and equals sign)

subtract row1 from row3, that eliminates x and z from row 3.

1  1   1  1
2  1  -1  8
0 -2   0  -6

divide row3 by -2, that will give y a factor of 1

1  1   1  1
2  1  -1  8
0 1   0  3

The last row now says y=3



3 0
3 years ago
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