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anyanavicka [17]
3 years ago
14

Find the measures of angels of M and NM (6y-10)N (4y-10)

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

We have been given an image of a trapezoid. We are asked to find the measure of angle M and N.

We know that bases of trapezoid are parallel and the two angles between two parallel lines are supplementary, so we can set an equation as:

\angle M+\angle N=180

(6y-10)+(4y-10)=180  

6y-10+4y-10=180

10y-20=180

10y-20+20=180+20

10y=200

\frac{10y}{10}=\frac{200}{10}

y=20

Upon substituting value of y in measure of angle M, we will get:

m\angle M=6y-10

m\angle M=6(20)-10

m\angle M=120-10

m\angle M=110

Therefore, measure of angle M is 110 degrees.

Similarly, we will find the value of angle N as:

m\angle N=4y-10

m\angle N=4(20)-10

m\angle N=80-10

m\angle N=70

Therefore, measure of angle N is 70 degrees.

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