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Shkiper50 [21]
3 years ago
7

Expand by using the distributive property: (a + bc)2x

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
5 0

2xa + 2xbc (just multiply both units in the paranthesis by whats on the outside.)

skad [1K]3 years ago
4 0

(a + bc)2x

= 2x*a + bc*2x

= 2ax + 2bcx

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What is the solution of x=2+ square root x-2?
alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

x-2=\sqrt{x-2}

Next, square both sides:

(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2

Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

x^2-2x-3x+6=0

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

x(x-2)-3(x-2)=0

Now you can rewrite the equation as (x-3)(x-2)=0

Now, apply the Zero Product Property and solve for x as such:

x-3=0\\x=3\\\\x-2=0\\x=2

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0
3 years ago
Carmen wants to join a gym. Gym A costs $26.76 plus an additional $4 for each visit. Gym B has no initial fee but costs $12.92 f
joja [24]

Answer:

After 3 visits both plans will cost the same.

Step-by-step explanation:

Gym A costs $26.76 plus an additional $4 for each visit.

Gym B has no initial fee but costs $12.92 for each visist.

The cost for gym A can be written as

C= $26.76 + 4(x)  where x is the number of visits to the gym A

The cost for gym B can be written as

C= $12.92 (x)  where x is the number of visits to the gym B

Both costs will be equal

12.92x= 26.76 +4x

12.92x-4x= 26.76

8.92x= 26.76

x= 26.76/8.92

x= 3

after 3 visits both plans will cost the same.

Check

12.92x= 26.76 +4x

12.92*3= 26.76 +12

38.76= 38.76

3 0
3 years ago
Add 4 kg 250 g, 2 kg 90 g and 19kg 3 g.
GarryVolchara [31]

Answer:

=25343 grams or 25 kg 343 g.

Step-by-step explanation:

1 kg = 1000 g

∴ 4 kg = 4000 grams

and the 4 kg 250 g would equal = 4250 grams.

∴ 2 kg = 1000 g

2 kg 90 g = 2000 grams + 90 g = 2090 grams

∴ 19 kg = 19000 grams

and 19 kg 3 grams = 19000 grams + 3 grams = 19003 grams

now we will add all of the values together to get the final answer.

4250 grams + 2090 grams + 19003 grams = 25343 grams or 25 kg 343 g.

Hope this helps!!

8 0
3 years ago
Enter the number of complex zeros for the polynomial function in the box.
Monica [59]

Answer:

The answer is 3.

Step-by-step explanation:

I took the quiz.

6 0
3 years ago
HELP PLEASE, Domain and range problem
pentagon [3]

Answer:

Range is number of copies produced and set of values is; 1 ≤ N ≤ 200

Domain; Cost of publishing book in dollars; set of values are; $710 ≤ N ≤ $2700

Step-by-step explanation:

Range is a set of all the possible output values in a function while domain is the set of all possible input values.

Now, the function is given as;

C = 10N + 700

Where;

C is the cost of publishing the book in dollars

N is the number of copies of books produced

Thus, the domain will be a set of N values while Range will be a set of C values.

We are told that the first printing can produce up to 200 copies of the book.

That means a maximum of 200 books and a minimum of 1.

Thus;

Range is; 1 ≤ N ≤ 200

Maximum possible cost of the 200 books is;

C = 10(200) + 700

C = $2700

Minimum cost which will be for 1 book will be;

C = 10(1) + 700

C = $710

Thus,domain is;

$710 ≤ N ≤ $2700

6 0
2 years ago
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