Answer:
The sample size required is, <em>n</em> = 502.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion is:
The margin of error is:
Assume that 50% of the people would support this political candidate.
The margin of error is, MOE = 0.05.
The critical value of <em>z</em> for 97.5% confidence level is:
<em>z</em> = 2.24
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B2.24%5Ctimes%20%5Csqrt%7B0.50%281-0.50%29%7D%7D%7B0.05%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D501.76%5C%5C%5C%5C%5Capprox%20502)
Thus, the sample size required is, <em>n</em> = 502.
Answer:
B
Step-by-step explanation:
Answer:
just look it up lol
Step-by-step explanation:
Answer:
4 cups of peanut butter, 2 cups of sugar, and 8 eggs.
Step-by-step explanation:
(1x4=4 + 1/2x4= 2 + 4x2=8)
Hope this helps!
Answer:
75
Step-by-step explanation:
Buddy and Ken can do work 2/3 times faster than Tom and Ron. The LCM (10, 15) is 30. In thirty minutes Buddy and Ken will have installed 3 panels, while Tom and ron will have installed 2 panels. In thirty minutes 5 panels will have been placed. There are 12 panels that need to be placed so we know it will take another thirty minutes to place 5 more panels. After an hour only 10 panels will have been placed. So we need to add more time. There are only two panels that will need to be placed after an hour, so each group can place a panel. Tom and Ron will need 15 minutes so the answer is 60+15=75.
