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Over [174]
4 years ago
7

You’re given two side lengths of 3 centimeters and 5 centimeters. Which measurement can you use for the length of the third side

to construct a valid triangle?
Mathematics
1 answer:
Ad libitum [116K]4 years ago
7 0
The third side (c) has to fit the equation a+b greater than or equal to c which must be greater than 0.

α+b ≥ c >0
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Is 5(2x-3y) equivalent to 10x - 3y? Please help me
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The answer would be false.
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3 years ago
Read 2 more answers
Please help I will give you the points ! Based on this information, which proportion is true?
Lelu [443]

Answer:

c

Step-by-step explanation:

im pretty sure its c. every other one is wrong except a and c. and the placement for a is wrong. so i think c.

4 0
3 years ago
Erica is training for a marathon This week she ran 6 less than 2 times the number of miles that she ran last week in these two w
Furkat [3]

Answer:

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7 0
2 years ago
The area of a rectangle is 21 yd.² and the length of a rectangle is 1 yard or less than twice the width find the dimensions of t
emmasim [6.3K]

Answer:

length = 6 yards

width = 3.5 yards

Step-by-step explanation:

the length of a rectangle is 1 yard less than twice the width

LEt 'w' be the width of the rectangle

and 'l' be the length of the rectangle

length l = 2 times the width -1

so l = 2w -1

Area of the rectangle = length * width

Area = l * w

we know length is 2w-1  and given area = 21

21 = (2w-1) * w

21= 2w^2 - w

subtract 21 on both sides

0= 2w^2 - w - 21

now solve for 'w'

0= 2w^2 +6w -7w- 21

0 = 2w(w+3)-7(w+3)

0= (2w-7)(w+3)

2w-7 = 0                    and w+3 =0

w = 7/2                            w=-3

width cannot be negative so we ignore w=-3

width w= 3.5

length = 2w-1= 2(3.5) - 1= 7-1=6

length = 6 yards

5 0
4 years ago
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