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Margaret [11]
3 years ago
15

A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.

the friction force on the sled is 1140 n and the angle between the two ropes is 25.0 ∘. how hard must each player pull to drag the coach at a steady 2.30 m/s ? assume both players pull with the same force.

Mathematics
1 answer:
masya89 [10]3 years ago
4 0
Refer to the diagram below, which provides a plan view of the problem

Because each player applies the same force, F, the angle between the force and the direction of motion is (1/2)*25° = 12.5°.

Because the sled  moves with constant velocity, the sled is in dynamic equilibrium, and
2F cos(12.5°) = 1140 N
1.9526 F = 1140
F = 583.84 N

Answer: 583.8 N (nearest tenth)

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Step-by-step explanation:

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Alex

Answer:

D =\frac{P}{\pi X^2}

And solving for the radius we got:

X = \sqrt{\frac{P}{\pi D}}

And replacing the data given we got:

X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km

And this value converted to meters is X = 87.40 m

Step-by-step explanation:

For this case we know the population size P = 20000 and we also know the population density D = 480 \frac{people}{km^2}

We can assume that the area is a circle. We also know that the formula for the population density is given by:

D= \frac{P}{A}

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

A = \pi X^2

With X the radius of the circle

And then the populationd density become:

D =\frac{P}{\pi X^2}

And solving for the radius we got:

X = \sqrt{\frac{P}{\pi D}}

And replacing the data given we got:

X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km

And this value converted to meters is X = 87.40 m

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Solve for the area of the combined shape
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Answer:

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Step-by-step explanation:

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I really need someone to answer this, QUICK!
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Answer:

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Step-by-step explanation:

A. 8/2=4/2=2  9/3=3   Use the denominators to find the LCM. In this case, the LCM is 72.

B.  35/5=7   63/3=21/3=7    The GCF for these numbers is 7 because it is the only factor that they have in common.

C.   7 x 14=88     Since 5 and 9 don't have common factors, they work perfectly for this problem.

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3 years ago
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katen-ka-za [31]

9514 1404 393

Answer:

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Step-by-step explanation:

The Law of Cosines can be rearranged to give the angle measure.

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The measure of angle Q is about 16.8°.

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