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xz_007 [3.2K]
3 years ago
13

Urgent I need the step by step on how to get this, I really appreciate it

Mathematics
1 answer:
aalyn [17]3 years ago
8 0

Answer:

The inverse of f(x) is g(y)=\frac{(y-8)^{2}}{4}+4

Step-by-step explanation:

Given function is given by f(x)=2\sqrt{x-4} +8

Let, y=f(x)=2\sqrt{x-4} +8

and g(y)=x is inverse of f(x)

Now,

f(x)=2\sqrt{x-4}+8

y=2\sqrt{x-4}+8

y-8=2\sqrt{x-4}

\frac{y-8}{2}=\sqrt{x-4}

\frac{(y-8)^{2}}{4}=(x-4)

\frac{(y-8)^{2}}{4}+4=x

\frac{(y-8)^{2}}{4}+4=x

g(y)=x=\frac{(y-8)^{2}}{4}+4

Thus, the inverse of f(x) is g(y)=\frac{(y-8)^{2}}{4}+4

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3 years ago
Solve the equation using square roots. Write your answer in simplest form.<br> Question in picture
GalinKa [24]

Answer:

The solutions to the quadratic equation involving square roots are:

x=2\sqrt{7}i+8,\:x=-2\sqrt{7}i+8

Step-by-step explanation:

Given the equation

\frac{1}{4}\left(x-8\right)^2+8=1

subtract 8 from both sides

\frac{1}{4}\left(x-8\right)^2+8-8=1-8

\frac{1}{4}\left(x-8\right)^2=-7

\left(x-8\right)^2=-28

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

solving

x-8=\sqrt{-28}

x-8=\sqrt{-1}\sqrt{28}

x-8=\sqrt{28}i       ∵ \sqrt{-1}=i

x=2\sqrt{7}i+8

similarly solving

x-8=-\sqrt{-28}

x-8=-2\sqrt{7}i

x=-2\sqrt{7}i+8

Therefore, the solutions to the quadratic equation involving square roots are:

x=2\sqrt{7}i+8,\:x=-2\sqrt{7}i+8

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Please help me I’m very confused
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Answer:

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Step-by-step explanation:

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MrRa [10]

Answer:

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Step-by-step explanation:

AD/BD=AC/BC

x/4.2=5/6

6x=21

6x/6=21/6

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Hope this helps! ;)

6 0
4 years ago
Read 2 more answers
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