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gayaneshka [121]
4 years ago
5

Find the differentiation y=root x​

Mathematics
2 answers:
ivanzaharov [21]4 years ago
8 0
Y= 1/(2 square root of x)
siniylev [52]4 years ago
5 0

Answer:

\frac{dy}{dx} = \frac{1}{2\sqrt{x} }

Step-by-step explanation:

Differentiate using the power rule

\frac{d}{dx}(ax^{n}) = nax^{n-1}

Given

y = \sqrt{x} = x^{\frac{1}{2} }, then

\frac{dy}{dx} = \frac{1}{2}x^{-\frac{1}{2} } = \frac{1}{2\sqrt{x} }

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Prove that Tan x + Cos x = 1 /Sin x .Cos x​
Anit [1.1K]

Answer:

tanx + cotx =  \frac{1}{sinxcosx}

Step-by-step explanation:

<u><em>Explanation</em></u>

Take R.H.S   = \frac{1}{sinxcosx}

            =      \frac{sin^{2}x+cos^{2}x  }{sinxcosx}

          =      \frac{sin^{2}x }{sinx cosx} + \frac{cos^{2} x}{sinxcosx}

        = \frac{sinx}{cosx} + \frac{cosx}{sinx}

        = tanx + cotx

tanx + cotx =  \frac{1}{sinxcosx}

             

5 0
3 years ago
Yes or no question plz answer i’ll give brainliest
Licemer1 [7]

Answer:

  yes

Step-by-step explanation:

Each x-value is only listed once, so the relation <em>is a function</em>.

__

A function maps each x-value to only one y-value. If an x-value is listed more than once (with different y-values), then the relation is not a function.

3 0
3 years ago
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What is 5 less than a product of 4 and a number?
Setler [38]
4x - 5
Or what kind of an answer are you looking for?
4 0
3 years ago
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Add the following numbers. -6 + 5 =
romanna [79]
-6 + 5
= -1.
Regards............
4 0
3 years ago
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In which quadrants do solutions for the inequality y ≤ 2/7x +1 exist?
viktelen [127]

All four quadrants

<h2>Explanation:</h2>

We have the following inequality:

y \leq \frac{2}{7}x+1

So the first step we need to perform is to plot the line:

y = \frac{2}{7}x+1

If \ x=0 \\ \\ y=\frac{2}{7}(0)+1 \\ \\ y=1 \\ \\ \\ If \ y=0: \\ \\ 0=\frac{2}{7}(x)+1 \\ \\ x=-\frac{7}{2}=-3.5

So the line passes through the points:

(0,1) \ and \ (-3.5,0)

To find the shaded region, let us take a point, namely, the origin and test it in the inequality:

y \leq \frac{2}{7}x+1 \\ \\ 0\leq \frac{2}{7}(0)+1 \\ \\ 0\leq 1 \ True!

Since this is true, then the shaded region includes this point. This is shown below and <em>as you can see the solutions exist in all four quadrants.</em>

<h2>Learn more:</h2>

Inequalities: brainly.com/question/12890742

#LearnWithBrainly

3 0
3 years ago
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