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trasher [3.6K]
3 years ago
15

If k(x) = 5x - 6, which expression is equivalent to (k + k)(4)?

Mathematics
2 answers:
ycow [4]3 years ago
5 0

\large \boxed{(k + k)(4) = k(4) + k(4)}

First, we find the value of k(4). We can find the value of k(4) by substituting x = 4 in k(x).

\large{k(x) = 5x - 6  \longrightarrow k(4) = 5(4) - 6} \\  \large{k(4) = 20 - 6 \longrightarrow 14}

Therefore the value of k(4) is 14. Next we find k(4)+k(4) which is equivalent to 14+14. Hence, the value of (k+k)(4) is 28. There's also another method.

\large \boxed{(k + k)(4) = 2k(4)}

As we know k(4) is 14. Therefore 2k(4) is 2×14 = 28.

Answer

  • (k+k)(4) = 28

kogti [31]3 years ago
3 0
28! hope this helps, you just plug in 4 for x, and then multiply by two.
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In that case, we can see that 4/3 is equivalent to 4 divided by 3

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Can side lengths 6 , 8 and 10 forms a right triangle .
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Step-by-step explanation:

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3 years ago
Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.
Vladimir [108]
\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt
\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k

Given \mathbf r(1)=\mathbf i+\mathbf j, we have

\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12

so that the particular solution is

\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k
8 0
3 years ago
Jennifer bought 3 bags of trail mix to make snack packs. She made 18 snack packs with trail mix. Write an equation to represent
Ber [7]
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3 0
3 years ago
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan
Crank

Answer:

<h3>2x + 5y = –15.</h3>

Step-by-step explanation:

We are given coordinates of the line passed through (–5, –1) and (10, –7) .

Applying slope formula,

Slope=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-5,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:-7\right)

Therefore,

m=\frac{-7-\left(-1\right)}{10-\left(-5\right)}

m=-\frac{2}{5}

Therefore, slope is m=-\frac{2}{5}.

Applying point-slope form y-y_1=m(x-x_1), we get

y+7 = -\frac{2}{5}(x-10)

y+7=-\frac{2}{5}(x-10)

On multiplying both sides by 5, we get

5(y+7)=5\times-\frac{2}{5}(x+1)

5y+35=-2(x-10)

5y+35=-2x+20

Adding 2x on both sides, we get

5y+25+2x=-2x+20+2x

2x+5y+35=20

Subtracting 35 from both sides, we get

2x+5y+35-35=20-35

2x+5y=-15.

Therefore, required equation is :

<h3>2x + 5y = –15.</h3>
6 0
3 years ago
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