Scalene,Acute i think it is haha
Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
35×69=35*69
35*69=2415
hopes this helps
Tell you what I'll do: I'll show you the work, for two of them.
Then, knowing how to do it, you'll find the answers.
Deal ?
#1). n + (-13) = -12
Remove the parentheses
on the left side: n - 13 = -12
Add 13 to each side: n = 1
================================
#3). -15 + n = 3
Add 15 to each side: n = 18
OK. Look those over, understand how they're done, then TAKE IT !
Hi!
For this equation, you can solve it by using the quadratic formula:
x=-b<span>±sqrt/b^2-4ab
-----------------------
2a</span>
