Answer:
Part 1) The segment length indicated is 
Part 2) The segment length indicated is 
Step-by-step explanation:
Let
x------> the segment length indicated
Part 1)
Applying the Pythagoras Theorem
Solve the quadratic equation by graphing
The solution is 
see the attached figure N 1
Part 2)
Applying the Pythagoras Theorem
Two previos numbers of <em>n</em><em> </em> are <em>(</em><em> </em><em>n</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em><em> </em> and <em>(</em><em> </em><em>n</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em> </em>Thus :
( n - 2) + ( n - 1 ) + n = 3n - 3
For starters,
tan(2θ) = sin(2θ) / cos(2θ)
and we can expand the sine and cosine using the double angle formulas,
sin(2θ) = 2 sin(θ) cos(θ)
cos(2θ) = 1 - 2sin^2(θ)
To find sin(2θ), use the Pythagorean identity to compute cos(θ). With θ between 0 and π/2, we know cos(θ) > 0, so
cos^2(θ) + sin^2(θ) = 1
==> cos(θ) = √(1 - sin^2(θ)) = 4/5
We already know sin(θ), so we can plug everything in:
sin(2θ) = 2 * 3/5 * 4/5 = 24/25
cos(2θ) = 1 - 2 * (3/5)^2 = 7/25
==> tan(2θ) = (24/25) / (7/25) = 24/7
Answer:
2(N-2)+14=
2(3-2)+14
2(1)+14
2+14
16
:)
Step-by-step explanation:
