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torisob [31]
3 years ago
7

What are the solutions of 3x2 + 14x + 16 = 0? x = , –2 x = –2, x = , 2 x = , 2

Mathematics
2 answers:
miskamm [114]3 years ago
7 0
Assume you mean 3x^2 when you typed the question.

3x^2+14x+16=0
(3x+8)(x+2)=0

x=-8/3 or -2
ycow [4]3 years ago
5 0

Answer:

option (A) is correct.

x = -2

Step-by-step explanation:

Given : equation 3x^2+14x+16=0

We have to solve for x,

Consider the given equation 3x^2+14x+16=0

we will solve the given quadratic equation using middle term split method, we have,

14x can be writen as 6x + 8x , we have,

3x^2+14x+16=0 \Rightarrow 3x^2+6x+8x+16=0

Taking 3x common from frst two terms and 8 common from lasttwo term , we have,

\Rightarrow 3x(x+2)+8(x+2)=0

Taking (x + 2) common, we have,

\Rightarrow (x+2)(3x+8)=0

Thus, Apply zero product rule, a\cdot b=0 \Rightarrow a =0 \ or\ b= 0

\Rightarrow (x+2)=0 or \Rightarrow (3x+8)=0

\Rightarrow x=-2 or \Rightarrow x=\frac{-8}{3}

Thus, option (A) is correct.

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Using a proportional relationship, we have that:

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  • b) The distance of two cities that are 5 miles apart is of 8 kilometers.
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<h3>What is a proportional relationship?</h3>
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