What are the solutions of 3x2 + 14x + 16 = 0? x = , –2 x = –2, x = , 2 x = , 2

Mathematics

2 answers:

miskamm [114]3 years ago

7 0

Assume you mean 3x^2 when you typed the question.

3x^2+14x+16=0
(3x+8)(x+2)=0

x=-8/3 or -2

ycow [4]3 years ago

5 0

Answer:

option (A) is correct.

x = -2

Step-by-step explanation:

Given : equation $3x^2+14x+16=0$

We have to solve for x,

Consider the given equation $3x^2+14x+16=0$

we will solve the given quadratic equation using middle term split method, we have,

14x can be writen as 6x + 8x , we have,

$3x^2+14x+16=0 \Rightarrow 3x^2+6x+8x+16=0$

Taking 3x common from frst two terms and 8 common from lasttwo term , we have,

$\Rightarrow 3x(x+2)+8(x+2)=0$

Taking (x + 2) common, we have,

$\Rightarrow (x+2)(3x+8)=0$

Thus, Apply zero product rule, $a\cdot b=0 \Rightarrow a =0 \ or\ b= 0$

$\Rightarrow (x+2)=0$ or $\Rightarrow (3x+8)=0$

$\Rightarrow x=-2$ or $\Rightarrow x=\frac{-8}{3}$

Thus, option (A) is correct.

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