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2 years ago

Help me out please help me

Mathematics

1 answer:

Paul [167]2 years ago

7 0

5x-22=3x+10
2x-22=10
2x=32
X=16

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Tentukan himpunan penyelesaian dari persamaan linear berikut .

Andreas93 [3]

A. Hope this helped im sorry if its wrong

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2 years ago

Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD?

lyudmila [28]

Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD? Yes, and the answer will be 180° so yeaaa, the statement is possible to intersect to AB and to the line CD.

Step-by-step explanation:

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2 years ago

The ratio for 3 turnovers : 12 assists as a fraction is?

slamgirl [31]

It is 3/12 and when you reduce it, it become 1/4

8 0

2 years ago

Read 2 more answers

D.sqrt(2+x^/2) Solve this question please

lidiya [134]

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

$y = \sqrt{4 + a*x^2}$

$y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }$

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

$y' = \frac{x*y}{2 + x^2}$

replacing y' and y we get:

$\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}$

Now we can try to solve this for "a".

$\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}$

If we multiply both sides by y(x), we get:

$\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}$

$a*x = \frac{x*(4 + a*x^2)}{2 + x^2}$

We can remove the x factor in both numerators if we divide both sides by x, so we get:

$a = \frac{4 + a*x^2}{2 + x^2}$

Now we just need to isolate "a"

$a*(2 + x^2) = 4 + a*x^2$

$2*a + a*x^2 = 4 + a*x^2$

Now we can subtract a*x^2 in both sides to get:

$2*a = 4\\a = 4/2 = 2$

Then the solution is:

$y = \sqrt{4 + 2*x^2}$

The correct option is option a.

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2 years ago

Find the equations that describe the circle of radius 2 centered at(5, 6, 1)that is parallel to the xy-plane. (enter your answer

Vladimir [108]

we know that

the equation of the sphere is equal to

$(x-h)^{2} +(y-k)^{2} +(z-l)^{2} =r^{2}$

where

(h,k,l) is the center of the sphere

r is the radius of the sphere

In this problem

the center is (5, 6, 1) and the radius is 2 units

the equation of the sphere is equal to

$(x-5)^{2} +(y-6)^{2} +(z-1)^{2} =2^{2}$

a) the equation of a circle that is parallel to the xy-plane is

For z=1

$(x-5)^{2} +(y-6)^{2} =2^{2}$

b) the equation of a circle that is parallel to the yz-plane is

For x=5

$(y-6)^{2} +(z-1)^{2} =2^{2}$

c) b) the equation of a circle that is parallel to the xz-plane is

For y=6

$(x-5)^{2} +(z-1)^{2} =2^{2}$

3 0

2 years ago

Help me out please help me​

Help me out please help me