<span>Wind farms are composed of tens of wind mills that us electric generator to harness the power of the wind. The power that comes out of the electric generators should be proportional with the force or the wind which is also proportional to the speed of the wind. Considering that a 10 m/s generates 500 kW, than a 12 m/s wind should generate somewhere around 600 kW.</span>
Answer:
$85 * thats how much he received
Answer:
105 feet or inches
Step-by-step explanation:
First we find the surface area of the base, (or the square.)
That is 25.
Next we find the areas of the triangle which is: 
×height
The area of one triangle is 20, so we multiply it by 4.
That is 80.
Finally, we add both surface area to find the total surface area.
That is 80 + 25 = 105
Hope that helped!
It looks like the given equation is
sin(2x) - sin(2x) cos(2x) = sin(4x)
Recall the double angle identity for sine:
sin(2x) = 2 sin(x) cos(x)
which lets us rewrite the equation as
sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)
Move everything over to one side and factorize:
sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0
sin(2x) - 3 sin(2x) cos(2x) = 0
sin(2x) (1 - 3 cos(2x)) = 0
Then we have two families of solutions,
sin(2x) = 0 or 1 - 3 cos(2x) = 0
sin(2x) = 0 or cos(2x) = 1/3
[2x = arcsin(0) + 2nπ or 2x = π - arcsin(0) + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
(where n is any integer)
[2x = 2nπ or 2x = π + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
[x = nπ or x = π/2 + nπ]
… … … or [x = 1/2 arccos(1/3) + nπ or x = -1/2 arccos(1/3) + nπ]
