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3 years ago

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The amount of W water used varies directly with the population N of people. City A has a population of 468,000 people and used 3

7.6 billion gallons of water we would expect City B to use if we know that it's population is 180,000.

1 answer:

ladessa [460]3 years ago

6 0

Answer:

the anser is 36.6 gallos of weeding in the w

Step-by-step explanation:

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Please answer this correctly

Contact [7]

Answer:

3 4, 5 0 6

Step-by-step explanation:

88,946 - 54,440 = 34,506

So missing number :

3 4, 5 0 6

8 0

3 years ago

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Answer this if you think I’m cute

otez555 [7]

Answer:

honey u the opposite of cute haha

Step-by-step explanation:

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A rhombus has a side length equal to one of the diagonals. The other diagonal is 4cm longer. Find the area of the rhombus.

klasskru [66]

Answer:

The area of the rhombus is 25.83 cm².

Step-by-step explanation:

The area of a rhombus is given by:

$A = \frac{d_{1} \times d_{2}}{2}$

Where:

d₁: is one diagonal

d₂: is the other diagonal = d₁ + 4 cm

We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:

h: hypotenuse of the right triangle

a: one side of the right triangle

b: is the other side of the right triangle

From the above we know that:

h = d₁

$a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2}$

$b = \frac{d_{1}}{2}$

We can find d₁ with Pitagoras:

$h^{2} = a^{2} + b^{2}$

$d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2}$

$d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2})$

By solving the above quadratic equation for d₁ and taking the positive solution we have:

$d_{1} = 5.46 cm$

So, d₂ is:

$d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm$

Now, we can find the area:

$A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2}$

Therefore, the area of the rhombus is 25.83 cm².

I hope it helps you!

3 0

3 years ago

Please help! Identify the asymptotes of the graph

klemol [59]

In this situation, the asymptopes are the dotted lines.

Looking at the graph, the equations of such lines are

X=2, Y=1

7 0

3 years ago

I need help figuring out the coordinate planes of these points ASAP.

d1i1m1o1n [39]

<u>Given</u>:

The vertices of the quadrilateral WXYZ are W(2,4), X(4,2), Y(2,1) and Z(0,2)

The graph is rotated 90° about the origin.

We need to determine the coordinates of the quadrilateral W'X'Y'Z'

<u>Coordinates of the quadrilateral W'X'Y'Z':</u>

The rule to transform the coordinates 90° counter clockwise about the origin is given by

$(x, y) \implies(-y, x)$

Let us substitute the coordinates.

The coordinates of W' is given by

$W(2,4)\implies W'(-4,2)$

The coordinates of X' is given by

$X(4,2) \implies X'(-2,4)$

The coordinates of Y' is given by

$Y(2,1) \implies Y'(-1,2)$

The coordinates of Z' is given by

$Z(0,2) \implies Z'(-2,0)$

Therefore, the coordinates of the vertices W', X', Y' and Z' are (-4,2), (-2,4), (-1,2) and (-2,0) respectively.

5 0

3 years ago