Number of babies=(58,400,000/1,000)*113=58,400*113=?
Answer:
2m^3n^3
Step-by-step explanation:
Let us start with the number parts
36 , 2 and 4
2 is common here as it can divide all
The smallest m factor is m^3 so it is common for all
The smallest n factor is n^3 which is also common for all
So, we have the greatest common factor as;
2 * m^3 * n^3 = 2m^3n^3
Answer:
m∠2 = 140°
Step-by-step explanation:
m∠1 = m∠3, since they're vertical angles.
Solve for x:

Plug in 6 for x for either m∠1 or m∠3. Doesn't matter since they're equal.
m∠1 = (2(6) + 28)°
m∠1 = (12 + 28)°
m∠1 = 40°
Now that we know m∠1, we can now solve for m∠2.
m∠1 + m∠2 = 180°
40° + m∠2 = 180°
m∠2 = 140°
The average rate of change on the interval (5, 6) is 9. So the correct option is D.
<h3>
How to find the average rate of change on the interval?</h3>
Here we want to find the average rate of change of f(x), the function on the table, on the interval (5, 6).
This is just:


I we look at the table we see that:



This is a system of equations.
If we subtract the second and first functions, we get:

From that we take two relations:

Now we can replace these two in the last equations so we get:

Now that we know the value of a:

The quadratic equation is:

Evaluating this in x = 6 we get:

And from the table we know that f(5) = 17, then the average rate of change is:

The correct option is D.
If you want to learn more about average rates of change:
brainly.com/question/8728504
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