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2 years ago

A 3-ounce serving of tuna fish provides 24 grams of protein. How many grams of protein are in a 19-ounce serving of tuna fish?

2 answers:

6 0

24/3 is 8, therefore there are 8 grams of protein per ounce of tuna. So 19*8 wld be 152.. there would be 152 grams of protein in a 19 ounce serving.

Ksju [112]2 years ago

4 0

Divide 24 by 3, you should get 8.
Then multiply 19 by 8.

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Given the function below, what value will result in f(x)=10? f(x)=1/2x+8

nignag [31]

10 = 1/2x + 8
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X = 4

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3 years ago

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Alik [6]

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2 years ago

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6 0

2 years ago

f^3+11g-4hf 3 +11g−4hf, cubed, plus, 11, g, minus, 4, h when f=3f=3f, equals, 3, g=2g=2g, equals, 2 and h=7h=7h, equals, 7.

Alik [6]

Given:

The expression is:

$f^3+11g-4h$

The given values are $f=3,\ g=2,\ h=7$ .

To find:

The value of the given expression for the given values.

Solution:

We have,

$f^3+11g-4h$

After substituting $f=3,\ g=2,\ h=7$ , we get

$f^3+11g-4h=(3)^3+11(2)-4(7)$

$f^3+11g-4h=27+22-28$

$f^3+11g-4h=49-28$

$f^3+11g-4h=21$

Therefore, the value of the given expression is 21.

8 0

2 years ago

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$

$y-4=\frac{-3}{4}(x+2)$

Hence the equation of line is found out

6 0

2 years ago