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3 years ago

A 3-ounce serving of tuna fish provides 24 grams of protein. How many grams of protein are in a 19-ounce serving of tuna fish?

2 answers:

6 0

24/3 is 8, therefore there are 8 grams of protein per ounce of tuna. So 19*8 wld be 152.. there would be 152 grams of protein in a 19 ounce serving.

Ksju [112]3 years ago

4 0

Divide 24 by 3, you should get 8.
Then multiply 19 by 8.

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I need help answering 1,2, and 3

EleoNora [17]

Answer:

I do not know sry

Step-by-step explanation:

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3 years ago

Read 2 more answers

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

8 0

3 years ago

Given the following two points find the slope. p1(-2,3)and p2(1,0)

Aloiza [94]

Answer

Slope(m) = -1

Step by step explanation

Slope (m) = (y2 - y1)/(x2 - x1)

Here p1 = (-2, 3) and p2 (1, 0)

x1 = -2, y1 = 3, x2 = 1, y2 = 0

Now plug in the values in the slope formula, we get

m = (0 - 3) / (1 - (-2))

m = -3/(1 + 2)

m = -3/3

m = -1

Therefore, slope = -1

Thank you.

8 0

3 years ago

1 - Graph a line with a slope of 4

AVprozaik [17]

Y=4x+2 that my equation now graph it

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3 years ago

Which equation represents the line that passes through the points (-3, 7) and (9,-1)? oy--3x+5 o y=-x-7 o y=zx-7 oy - 12 2x+5

nekit [7.7K]

Answer:

use the slope equation (y2-y1) / (x2 -x1). plug in values and solve

(-1 -7) / (9 -(-3)) (subtracting a negative is the same as adding a positive)

-8 / 12 (simplify)

m = -2/3

then, plug in one of the points and the slope into the slope-point equation.

(y - y1) = m (x - x1) (the point-slope form)

y - 7 = -2/3( x - (-3)) (plug in the slope and point 1 values, then solve)

y - 7 = -2/3x - 2 (add 7 to both sides)

y = 2/3x +5 (the answer)

Step-by-step explanation:

I hope this helps :))

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3 years ago