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seraphim [82]
3 years ago
8

Proving trapezoid theorems Geometry

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0

Answer:

ΔABD ≅ ΔACD by SAS, therefore;

\overline {BD} \cong \overline {CA} by CPCTC

Step-by-step explanation:

The two column proof is presented as follows;

Statement {}                   Reason

ABCD is a trapezoid {}  Given

\overline {BA} \cong \overline {CD}  {}                   Given

\overline {BC} \parallel \overline {AD}   {}                   Definition of a trapezoid

ABCD is an isosceles trapezoid  {}    Left and right leg are equal

∠BAD ≅ ∠CDA  {}          Base angle of an isosceles trapezoid are congruent

\overline {AD} \cong \overline {AD}   {}                  Reflexive property

ΔABD ≅ ΔACD   {}         By SAS rule of congruency

\overline {BD} \cong \overline {CA}   {}                  CPCTC

CPCTC; Congruent Parts of Congruent Triangles are Congruent

SAS; Side Angle Side rule of congruency

Vilka [71]3 years ago
5 0

Answer:

Step-by-step explanation:

just did it

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Answer:

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Step-by-step explanation:

The question will be solved using the permutation formula since are arranging. <u>Permutation deals with arrangement.</u>

If there we are to arrange n objects taking 'r' at a time, this can be done in nPr ways.

nPr = \frac{n!}{(n-r)!}

a) If you therefore have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. Since they are in a single file line, This can be done in 6P3 number of ways.

6P3 = \frac{6!}{(6-3)!}\\ 6P3 = \frac{6!}{3!}\\ 6P3 = \frac{6*5*4*3!}{3!} \\6P3 = 6*5*4\\6P3 = 120\ ways

b) The number of unique ways to arrange the letters in the word DEN is 3! ways since there are only 3 letters in the word.

3! = 3*2*1

3! = 6ways

8 0
3 years ago
HELP PLSS I DONT WANNA FAIL
posledela

Answer: 1/2 and 3/6

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Jobisdone [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
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