F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
10833 because Albert Einstein went to the moon and back 42000
I could be wrong but I’m pretty sure the analysis stage
T>L+D/B
(Assume no parentheses missing and use PEMDAS rule)
Subtract L from both sides
T-L > L-L + D/B
T-L>D/B
Multiply both sides by B (assuming B>0)
B(T-L)>D/B*B
B(T-L)>D
Interchange two sides,
D<B(T-L) (if B>0)
if B<0, then D>B(T-L)
Answer:
cost of a taco: $1.25
cost of a burrito: $2.50
Step-by-step explanation:
Let the cost of a taco be $t and the cost of a burrito be $b.
t +3b= 8.75 -----(1)
4t +2b= 10
Divide both sides by 2:
2t +b= 5
Making b the subject of formula:
b= 5 -2t -----(2)
Substitute (2) into (1):
t +3(5 -2t)= 8.75
Expand:
t +3(5) +3(-2t)= 8.75
t +15 -6t= 8.75
t -6t= 8.75 -15
-5t= -6.25
t= -6.25 ÷(-5)
t= 1.25
Substitute t= 1.25 into (2):
b= 5 -2(1.25)
b= 5 -2.5
b= 2.50
Thus, the cost of a taco is $1.25 and the cost of a burrito is $2.50.
