A=850×(1+0.08)^(8)
A=1,573.29
Interest 1573.29-850=723.29
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
false
Step-by-step explanation:25.9cm is too big to connect to 15.9cm and 10 cm
A^2+ b^2= c^2
24^2+b^2=25^2
576+b^2=625
Sub 576
b^2= 49 b=7
Answer:
<u>242 sq. cm.</u>
Step-by-step explanation:
<u>Surface Area</u>
- 2(LH + BH + LB)
- 2(10 × 3 + 7 × 3 + 10 × 7)
- 2(30 + 21 + 70)
- 2(121)
- <u>242 sq. cm.</u>
