The alue of 5 is the tenths place.
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
Answer:
22x+27
Step-by-step explanation:
Let's simplify step-by-step.
9(2x+3)+4x
Distribute:
=(9)(2x)+(9)(3)+4x
=18x+27+4x
Combine Like Terms:
=18x+27+4x
=(18x+4x)+(27)
=22x+27
Answer:
5
Step-by-step explanation:
i did 300 divided by 60%