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2 years ago

Substitute the given values into the formula, and solve for the unknown variable. A=bh; A=6, h=6

Mathematics

1 answer:

Murrr4er [49]2 years ago

8 0

6=b6 which you’ll have to divide by 6 on both sides leading to B=1

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At a certain electronics company, the daily output Q is related to the number of people A on the assembly line by Q=600+√(A+41).

Ber [7]

Answer:

$A=400\ people$

Step-by-step explanation:

we have

$Q=600+\sqrt{A+41}$

where

Q -----> is the daily output

A -----> is the number of people

For Q=621

Find the value of A

substitute and solve for A

$621=600+\sqrt{A+41}$

Subtract 600 both sides

$621-600=\sqrt{A+41}$

$21=\sqrt{A+41}$

squared both sides

$21^{2} ={A+41}$

$441={A+41}$

Subtract 41 both sides

$441-41=A$

Rewrite

$A=400\ people$

3 0

2 years ago

Evaluate the function f(x) = 3x2− 2x for x= 4.

kykrilka [37]

Answer:

Step-by-step explanation:

f(4) = 3(4²) - 2(4)

= 3(16) - 8

= 48 - 8

= 40

when x=4, f(x) = 40

6 0

2 years ago

In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°