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Yakvenalex [24]

3 years ago

7

How many times as much does each item cost in 2010 as in 1960 is the movie tix it tickets in 1960 costed $.75 in in 2010 cost 9.

75

2 answers:

Harrizon [31]3 years ago

8 0

13 times i think
You just divide 9.75 by .75 and you get 13

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

13 times.

Step-by-step explanation:

It is given that,

Cost of movie tickets in 1960 = $0.75

Cost of movie tickets in 2010 = $9.75

We need to find how many times as much does each item cost in 2010 as in 1960.

Let x times as much does each item cost in 2010 as in 1960.

$0.75\times x=9.75$

$x=\dfrac{9.75}{0.75}$

$x=13$

Therefore, cost of each item in 2010 is 13 times as in 1960.

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Find the length of the missing side. Leave your answer in simplest radical form.

Hatshy [7]

Answer:

The SQ Root of 493

Step-by-step explanation:

Becaues this triangle is a right triangle, we can find the missing side usiing the pythagorean theorum.

The pythagorean theorun states A^2 + B^2 = C^2, so 18^2 + 13^2= 439

Then all you have to do is find the sq root of 439, but this question askes you not to.

Hope this helps :)

7 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

4 years ago

What is the volume of a cube whose edges each have a measure of 1.6cm?

Finger [1]

B is the answer
${1.6}^{3} = 4.096$
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8 0

3 years ago

How to Graph 3(x-2)2+6

BARSIC [14]

Answer:

n/a

Step-by-step explanation:

it just needs more work on the vertex.

3 0

3 years ago

ben plays basketball every 6 times in 3 weeks. At this rate, how many times does he play basketball in 10 weeks

Ratling [72]

Answer:

18

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers