Y = T+3 (i)
T = H+2 (ii)
Y = 2*H (iiii)
T = H+2 therefore H = T-2
Substitute H=T-2 into (iii)
Y=2*H
Y=2*(T-2)
Y=2T-4
Now substitute that Y into (i)
(i) says Y = T+3
2T-4=T+3
2T-T-4=3
T-4=3
T=3+4
T=7
Then from (i) Y=T+3 = 7+3 =10
Y=10
And from (iii) Y=2*H
If Y = 10, then H = 5
Jeff has -15$ his gf faith gives him 7.
The first equation is

The second equation is

If you sum the two equations you'll cancel y:

And since the sum must be 11, we have y=9.
x+3-1.26923+4.12821 so if I am wrong it took me a while to work this out