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german
3 years ago
5

The two trapezoids shown below are similar . What is the length of x?

Mathematics
2 answers:
dangina [55]3 years ago
7 0
The length of x is 3. Since the two trapezoids are similar. In the second trapezoid the top is half of 10. so it would be logical for x to be 3
serious [3.7K]3 years ago
6 0
The length of x is 3
mark me brainliest if the answer is correct, thank you in advance :)
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What is the measure of arc AC?
8_murik_8 [283]

If Im not mistaken, the answer should be d because if you add all the degrees up, then you would get 222. And if you subtract 360 from 222 you get 138. I hope this helps. :)

7 0
3 years ago
If ON = MN, find MN.
Furkat [3]
Use Pythagorean theorem.

[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}

Answer: |MN| = 4√2.
4 0
3 years ago
Dose anyone know how to solve this??
AfilCa [17]

Answer:

....................

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=3x%5E3%20-%207x%5E2%20%5C%20x" id="TexFormula1" title="3x^3 - 7x^2 \ x" alt="3x^3 - 7x^2 \ x"
MaRussiya [10]
X(3x^2-7x+1)
You can only factor out a “x”
6 0
3 years ago
A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>
6 0
2 years ago
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