The second and third ones are the true ones
Let's say the cost of student tickets is x and the cost of adult tickets is y. Then:
(1) 12y + 6x = 138
(2) 5y + 11x = 100
If we rearrange equation (1) we get:
12y = 138 - 6x
Now divide each side by 12:
y = 11.5 - 0.5x
We can now substitute this into equation (2):
5(11.5 - 0.5x) + 11x = 100
57.5 - 2.5x + 11x = 100
8.5x = 42.5
x = 5, therefor the cost of a student ticket is $5.00
Answer:
b+3+6c, 27n+66p ,12x + 75y + 21
Step-by-step explanation:
Answer:
h(5) = 7
Step-by-step explanation:
Step 1: Define
h(x) = 2x - 3
h(5) is x = 5
Step 2: Substitute and Evaluate
h(5) = 2(5) - 3
h(5) = 10 - 3
h(5) = 7
