The statement is false, as the system can have no solutions or infinite solutions.
<h3>
Is the statement true or false?</h3>
The statement says that a system of linear equations with 3 variables and 3 equations has one solution.
If the variables are x, y, and z, then the system can be written as:
Now, the statement is clearly false. Suppose that we have:
Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.
Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.
If you want to learn more about systems of equations:
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Answer:
I don't know
Step-by-step explanation:
How you will find out the value of 'n ' ?
[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]
1. y = -1/2 + 2.
2. y= 2/5x - 4/5
<span>D) perpendicular bisector <em>I believe.
</em></span>
Answer:
5/10×4/6=1/3
Solution with Steps
5/10×4/6=?
For fraction multiplication, multiply the numerators and then multiply the denominators to get
20/60
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 20 and 60 using
GCF(20,60) = 20
(rest is in image)
HOPE THIS HELPED