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3 years ago

Help me with this question

Mathematics

1 answer:

MaRussiya [10]3 years ago

6 0

Answer:

Step-by-step explanation:

In kilograms, just move the decimal right before the first digit and multiply it by ten to the power of how many times you moved the decimal:

6.20 x 10^6

In grams, change 6,200,000 kg to g. One kg is 1000 g, so divide 6,200,000 by 1000. This would equal 6200 g. Now, move the decimal right before the first digit and multiply it by ten to the power of how many times you moved the decimal:

6.20 x 10^3

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In an arithmetic sequence, the nth term an is given by the formula an=a1+(n−1)d, where a1 is the first term and d is the commo

Dmitry_Shevchenko [17]

Answer:

$a_{10} = \frac{10}{65536}$

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

$a_{3} - a_{2} = a_{2} - a_{1}$

We have that:

$a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}$

$a_{3} - a_{2} = a_{2} - a_{1}$

$\frac{5}{2} - 10 = 10 - 40$

$\frac{-15}{2} \neq -30$

This is not an arithmetic sequence.

This sequence is geometric if:

$\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}$

$\frac{\frac{5}[2}}{10} = \frac{10}{40}$

$\frac{5}{20} = \frac{1}{4}$

$\frac{1}{4} = \frac{1}{4}$

This is a geometric sequence, in which:

The first term is 40, so $a_{1} = 40$

The common ratio is $\frac{1}{4}$ , so $r = \frac{1}{4}$ .

We have that:

$a_{n} = a_{1}*r^{n-1}$

The 10th term is $a_{10}$ . So:

$a_{10} = a_{1}*r^{9}$

$a_{10} = 40*(\frac{1}{4})^{9}$

$a_{10} = \frac{40}{262144}$

Simplifying by 4, we have:

$a_{10} = \frac{10}{65536}$

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3 years ago

What is the volume of the triangular prism

mestny [16]

Answer:

308 cm³

Step-by-step explanation:

The volume is:

V = Bl = 1/2(ah)l
V = 1/2(7*8)*11 = 308 cm³

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The answer is 35.35294

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Answer:

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Step-by-step explanation:

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