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Marat540 [252]
3 years ago
10

In one town, 4% of 18-29 year olds own a house, as do 21% of 30-50 year olds and 55% of those over 50. According to a recent cen

sus taken in the town, 28.9% of adults in the town are 18-29 years old, 39.4% are 30-50 years old, and 31.7% are over 50. What is the probability of an adult owning a house in this town?
A) 0.027
B) 0.186
C) 0.269
D) 0.267
Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
I think my answer will be A .
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Help me please with this
prisoha [69]
To factor this collect the like terms..2y would go with -7y to make -5y etc. Then factor the expression by factoring out 9 Your final answer should be 9(1-y+x^2)

If you need to simplify this calculate the sum or difference between numbers (3-1+7=9)
Your final answer for this should be 9-9y+9x^2

Hope this helps!
6 0
3 years ago
5 2/7+1 2/7 as a mixed number in simplest form
marusya05 [52]

Answer:

6 4/7

Step-by-step explanation:

I personally break it down like this:

Is 2 greater than 7? No so that means the whole number would stay 5.

Same for the other number. Then add the whole numbers attached to the fraction. Which is 6. Then go to the fraction. 2/7 + 2/7 is 4/7. This cannot be simplified anyfurther.

5 0
2 years ago
Read 2 more answers
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
Trey has bought 10 pounds of dog food. He feeds his dog
inna [77]

how many pounds does he feed his dogs for each meal?

8 0
2 years ago
Olivia flips a two-sided counter and then spins a spinner with six equal-size sections labeled 1 through 6. One side of the coun
Novay_Z [31]

Answer:

12

Step-by-step explanation:

A 2 - sided counter ; (red, yellow)

A spinner (1,2,3,4,5,6)

Number of trials = 80

P(red and number > 3) :

P(red) = 1/2 ;

P(number >3) : numbers greater Than 3 = (4, 5, 6)

Hence, P(number <3) = 3 /6 = 1/2

Theoretical probability = 1/2 *1/2 = 1/4

Expected number of outcomes :

1/4 * number of trials

1/4 * 80 = 20

Experimental outcome :

Relative frequency = number of outcomes / number of trials

Relative frequency = 2/5

Hence,

2/5 = number of outcomes / 80

Cross multiply :

160 = number of outcomes * 5

Number of outcomes = 160 /5 = 32

Actual outcomes = 32

Difference between actual and expected :

32 - 20 = 12

7 0
3 years ago
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