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4 years ago

9

Help please!!! In y = mx + b form

1 answer:

nekit [7.7K]4 years ago

4 0

Answer: y=7+-7

Step-by-step explanation:

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Marie made the box plot below to display a set of data. Which set of data could the box plot represent?

Assoli18 [71]

Answer:

see below

Step-by-step explanation:

First of all, you want to find the data set the matches the extreme values of 5 and 35. That eliminates the 2nd and 4th choices.

Then you want to find the data set that has a median of 15. The first data set has a middle value (median) of 20, so that choice is eliminated.

The data set of the 3rd choice matches the box plot extremes, median, and quartile values.

7 0

3 years ago

What type of line is the graph of y = 7?<br><br> Vertical<br> Horizontal<br> Rising<br> Falling

Ksivusya [100]

The line y = 7 would just be a Horizontal line on 7
Basically, you go up 7 units then draw a straight horizontal line across
Hope this helps!

5 0

3 years ago

Read 2 more answers

Help pleaseeeeeeeee?!?!

nalin [4]

Strong, they are all close together and close to the line.

5 0

3 years ago

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Write the polynomial in factored form.<br><br> x^3−3x^2−10x

kirill115 [55]

Answer:

x( x − 5 ) ( x + 2 )

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers