Answer:B
I got it right on my test
Step-by-step explanation:
 
        
             
        
        
        
Hey there,
Your question states: You have a 332 feet fencing to enclose a rectangular region. What is the maximum area.
Your correct answer would be 
6,889.Reason/explanation: The formula that we would use is 



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So by this, now that we know that 

We do . . . 83 × 83. . . 
And you final answer would be 
Option A.) 6,889Hope this helps you!
~Jurgen
 
        
        
        
Answer:
81
Step-by-step explanation:
 
        
             
        
        
        
Let x =lenght, y = width, and z =height 
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>