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2 years ago

I need a answer right now I’ll give you points!

Mathematics

2 answers:

Kipish [7]2 years ago

8 0

Answer:

100% right answer

satela [25.4K]2 years ago

3 0

Answer:

G. 118°

Step-by-step explanation:

Imagine a line, parallel to AD, that passes through B to a point x on the line CD.

∠CBX=∠CAD=28 (corresponding angles)

∠EBX=90 (BX║ED, BE║XD)

∠CBE=∠CBX+EBX

∠CBE=28+90

∠CBE=118°

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What is eight more than one fourth of d

adoni [48]

Answer:

1/4d+8.

hope this helps please make brainliest

Step-by-step explanation:

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2 years ago

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If a sequence contains only whole numbers, which of these sequences could include the term 27?

erik [133]

Depending on the first term, the sequences
$a_n=2a_{n-1}+1
\\
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\\a_n=a_{n-1}+6$
would work.

If the sequence began at 6,
$a_n=2a_{n-1}+1=6, 13, 27, ...$

If the sequence began at 1,
$a_n=3a_{n-1}=1, 3, 9, 27, ...$

If the sequence began at 3,
$a_n=a_{n-1}+6=3, 9, 15, 21, 27, ...$

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3 years ago

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Proportional relationships, please answer all of the parts! Thank you!

Natalka [10]

Answer:

a. No (see below)

b. (see below)

c. Johnny

d. Johnny = $12.50 / hour Doug = $9.16... / hour

e. Doug: extend the table to show how much he gets paid for 1 hour of work (the unit rate)

Johnny: already on the graph

Step-by-step explanation:

a. No. This is because a proportional relationship would have a certain ratio between payment and the amount of time spent working, which would not change. However, if Doug's neighbour pays him $55 for 6 hours, it's likely that this is not a proportional relationship, or we would be able to divide $55 by the 6 hours Doug spent working.

b. Even though above I said that it's probably not a proportional relationship, if it were, we would have to divide everything equally. I'm guessing the table should look like this:

Doug

Time (hr) Earnings ($)

4 $36.66...

5 $45.8333...

6 $55

7 $64.4666....

8 $73.333...

To work out how much Doug would get for working 4 hours:

4/6 x $55 = 2/3 x $55 = $36.66... (so definitely not a proportional relationship)

To work out how much Doug would get for working 5 hours:

5/6 x $55 = $45.8333.... (more evidence that this is not a proportional relationship)

To work out how much Doug would get for working 7 hours (we already got 6 hours):

7/6 x $55 = $64.4666...

To work out how much Doug would get for working 8 hours:

8/6 x $55 = $73.33... (we could double the 4 hour payment, but this is probably more accurate)

c. Johnny is getting paid more. If we look at how much Doug gets for 6 hours, it's $55. If we look out at how much Johnny gets for 6 hours, it's $75. (If we do the same with the other amounts of time, it's the same.

4 hours: D = $36.67 vs J = $50

5 hours: D = $45.83 VS J = $60

etc...

d. Johnny gets $75 per 6 hours --> 75/6 = $12.50 per hour

Doug gets $55 per 6 hours --> 55/6 = $9.1666... per hour

e. Carry on the table for Doug all the way to 1, so you can see the how much Doug gets paid for 1 hour of work (i.e. the minimum).

The unit rate is already on the graph for Johnny.

HOPE THIS HELPED :)

P.S. Mate cld you please give me Brainliest? That table took so much dam work

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3 years ago

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What percent us 28 of 70?

RoseWind [281]

$\displaystyle\\
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3 years ago

Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut

defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .