Hi there! The answer is A.
Graph A. is not linear because it contains x^2 and therefore is a quadratic function.
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
Step-by-step explanation:
A
Answer: SAS
Step-by-step explanation:
There is an angle B or D and the sides being the 26, 21, and 32! (Sorry if I get it wrong)
The answer is D. -2x+5.
If we simplify the left side of the equation first given, we come to the expression -2x-10.
If we solve for D., we get the same results. Thus, because an equation with all the same variable terms and constants have infinite solutions, the answer is D.
Hope this helps!
