Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
I realise this is quite late but in case you still wanted the answer, the width is 3m.
If the length is 3m longer than the width, you can write the width as x and the length as x + 3. The perimeter would be both lengths and both widths added together, so you would just write it as:
x + x + x + 3 + x + 3 = 18
4x + 6 = 18
- 6
4x = 12
÷ 4
x = 3
I hope this helps!
Step-by-step explanation:
u take the fox over to the other side, then the chicken feed then the chicken.
Number of outcomes of rolling a die = 6
Number of outcomes from the spinner = 8
First we have to draw the 6 leaves to represent the 6 outcomes of rolling the die. Next on each of these leaves 8 possible outcomes of the spinner will be drawn using leaves.
So 6 leaves are being divided into further 8 leaves.
Thus total number of leaves will be = 6 x 8 = 48 leaves
Therefore, the correct answer is option D
