<span>Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers.
Scottie's are 3 more than schnauzers. So their number is x+3
Wire haired terriers are 5 less than twice the number of schnauzers.
So their number is 2x -5 (2x for twice the number of schnauzers)
Now add all these numbers.
That is x + x+3 + 2x-5 = 4x -2
The total number of dogs, 78, is given in the question
Now we know that 4x -2 =78
4x = 78 +2
= 80
Therefore x = 80/4
= 20.
So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers</span>
Could you provide the answer choices please?
The answer is $2.50 because you do 145-132.50=12.5
Then you divide by 5 because that’s the difference between students then the final answer is 2.50
50p=c
So $50 x the number of people = the price in dollars
So for 11 people it would cost $550
I hope this helped :)
For part B
the fixed cost is 500 dollars because it is a set inital amount, the varibale cost is .15 because it is the cost dependent on something else (per indicated variable part)
y=.15x+500
.15 cents per flyer, add 500 because that is the set amount it costs to even create the flyer
Plug in 500 for the equation
y=.15(500)+500
y=75+500
y=575
for part a
b=ka for direct variations so the direct one is C - two items directly multiplied
y=mx+b for partial variation so its A,D - basically the equation of a line
A is neither - shows neither of these relationships
