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3 years ago

Jada fills the bathtub before taking a bath and then allows the water to drain

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

Tell me the question and I will get back to you

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Write the number that is poitioned at point b

defon

Answer:

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2 years ago

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Larry bought 12 containers of pasta salad for a school picnic. Each container held the same number of ounces of salad. Students

tester [92]

Answer:

12 p - 8 p, 4p ( 3 - 2)

Step-by-step explanation:

p = equal the number of ounces of pasta salad in one container

then 12 × p = 12 p in 12 containers

the students finished the pasta salad in 8 containers which equals = 8 p

the number of ounces of pasta left = 12 p - 8 p

b) using the distributive property for example a ( b + c) = ( a×b) + (a ×c)

12 p - 8 p = 4p ( 3 - 2)

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3 years ago

Help please.........

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Step-by-step explanation:

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3 years ago

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Is 3x + 2y = 6 a function??

professor190 [17]

Answer:

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Step-by-step explanation:

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2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago