Answer:

Step-by-step explanation:
The equation of a parabola in vertex form:

<em>(h, k)</em><em> - vertex</em>
The focus is

We have the vertex (2, -5) and the focus (2, -4).
Calculate the value of <em>a</em> using 
<em>k = -5</em>
<em>add 5 to both sides</em>
<em>multiply both sides by 4</em>


Substitute

to the vertex form of an equation of a parabola:

The standard form:

Convert using


<em>use the distributive property: a(b+c)=ab+ac</em>

Answer: 452.16 or just 452 units^3
Step-by-step explanation:
V= πr^2*h
using 3.14 like the problem asks could effect what you're rounding to but either way pi(6)^2=113.04 *4= 452.16
Answer:
8$
Step-by-step explanation:
4 students contribute 12$ Each.
So, total amount becomes 12 x 4 = 48$
If two more students contribute it makes a total of 6 students.
so we now divide the 48$ by 6
48/6=8$
Answer:
The answer is 527.5km^3 .
Step-by-step explanation:
The formula for cylinders is πr2h. (pie times twice the height)
3.14(12)(2)(7) = 527.52
Answer:
Ted is correct. Maggie made mistakes while trying to isolate x for both equations.
Step-by-step explanation:
For 3x-2=0, in order to move -2 to the left side, Maggie had to add 2 on both sides because -2+2=0. The same problem is seen for x+5=0. Maggie had to subtract 5 on both sides because +5-5=0