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2 years ago

13

Help plz asap,soon!!!!!!!!!!!!

1 answer:

aniked [119]2 years ago

3 0

I think it is 12x+y=48

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Evaluate 2d+32 when d=8.

Sloan [31]

Given $2d+32$

$d=8$

Put the value of d in the given equation

$2d+32$

$2(8)+32$

$16+32$ $= 48$

What we do in Evaluation in math?

The verb "evaluate" is used in mathematics to mean to discover or determine the worth of something. Finding the precise value of an algebraic expression or numerical computation is relevant here as well as financial mathematics.

In mathematics, the terms "evaluate" and "solve" are often used interchangeably. Consider the following basic multiplication problem: "Evaluate the cost of six tomatoes when the tomatoes are purchased at $2 each." The student would multiply 6 by 2 to get the result of $12. The term evaluate might also come before a list of inquiries, as a list of straightforward algebraic equations.

Learn more about Evaluate brainly.com/question/23574746

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8 0

1 year ago

The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,

klasskru [66]

Given:

The scale factor is $s=\dfrac{1}{3}$ and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

$(x,y)\to (k(x-a)+a,k(y-b)+b)$

According to the given information, the scale factor is $\dfrac{1}{3}$ and the center of dilation is at (4,2).

$(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)$ ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

$C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)$

$C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)$

$C(-2,11)\to C'(-2+4,3+2)$

$C(-2,11)\to C'(2,5)$

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

$A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)$

From the given figure it is clear that the image of point A is (8,4).

$A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)$

On comparing both sides, we get

$\dfrac{1}{3}(m-4)+4=8$

$\dfrac{1}{3}(m-4)=8-4$

$(m-4)=3(4)$

$m=12+4$

$m=16$

And,

$\dfrac{1}{3}(n-2)+2=4$

$\dfrac{1}{3}(n-2)=4-2$

$(n-2)=3(2)$

$n=6+2$

$n=8$

Therefore, the coordinates of point A are (16,8).

5 0

2 years ago

For f(x)=13^x,find f(3/2)

tekilochka [14]

Answer:

f(3/2) = 13√13 ≈ 46.872167

Step-by-step explanation:

Put 3/2 where x is and evaluate.

f(3/2) = 13^(3/2) = 13^(1 +1/2) = 13√13

f(3/2) ≈ 46.872167

5 0

2 years ago

PLz help asap CONGRUENCE WILL GIVE BRAINLIEST

Elza [17]

Same idea as last time only the similar angles are 92 and 92. Thus your anwser: 92

8 0

3 years ago

What is 3×10^-2 in standerd notation??

Gemiola [76]

Answer: 0.03

Step-by-step explanation:

7 0

2 years ago