Answer: Glucose (C6H12O6) is a hexose -- a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains a -CHO group). Five of the carbons plus an oxygen atom form a loop called a "pyranose ring", the most stable form for six-carbon aldoses.
Explanation:.
Molarity = 1.5
molarity = moles/liters
m= 3/2
m= 1.5
Answer:
1.68L
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial Molarity (Mi) = 7M
Initial volume (Vi) 0.6L
Final Molarity (Mf) = 2.5M
Final Volume (Vf) =.?
Step 2:
Determination of the final volume of the solution.
This can be achieved as shown below:
MiVi = MfVf
Divide both side by Mf
Vf = MiVi /Mf
Vf = 7 x 0.6 / 2.5
Vf = 1.68L
Therefore, the new volume of the solution is 1.68L
