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2 years ago

9

Issue like gay marriage, abortion, and education have caused debate over the constitution because of the issue of what? (Hint: f

ederalism)

1 answer:

Korolek [52]2 years ago

3 0

Yes 81671 cupcake ham shops

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In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water b

Katen [24]

Answer:In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?

Explanation:

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2 years ago

Which form of energy can be connected closely to climate change?

Art [367]

Answer:

COAL

Explanation:

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3 years ago

What purpose does ammonia lauryl sulfate serve as a surfactor

Alborosie

Answer:

See below

Step-by-step explanation:

Ammonium lauryl sulfate has the structural formula CH₃CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₂OSO₂O⁻ NH₄⁺.

The long nonpolar hydrocarbon chain and the ionic sulfate end group make it a surfactant.

The ionic end tends to dissolve in water, but the nonpolar chain does not. This makes the compound an excellent <em>foaming agent,</em> so it is used in many shampoos and toothpastes.

The molecules form <em>micelles</em> in water, small spherical shapes with the polar heads outside, facing the water, and the nonpolar tails are inside.

They reduce the surface tension or the water so that, when you brush your teeth or shampoo your hair, the air bubbles are stable and do not break.

8 0

3 years ago

CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

<u>Answer:</u> The $\Delta G$ for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

7 0

3 years ago

What do the conclusions tell about the experiments?

Anni [7]

Answer:

the answer would be C of not C is B

4 0

3 years ago

Read 2 more answers