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Yuki888 [10]
3 years ago
7

Can pH be less than zero???

Chemistry
1 answer:
k0ka [10]3 years ago
8 0

Answer:

No.

Explanation:

It can be from 1 to 14.

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What if you measured 15cc of liquid elemental mercury, how much would that weigh in pounds
PIT_PIT [208]

Answer:

0.447 pounds

Explanation:

The density of Mercury in grams/mL is 13.55 - I multiplied that by the volume and got approximately 203.25 grams, I then turned it into Kilograms and multiplied by 2.2 lbs / kg.

4 0
3 years ago
Identify the type of igneous rock that is formed when magma cools above Earth's surface?
mylen [45]

Answer: cools down and keeps going

Explanation:

5 0
3 years ago
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
A chemist dilutes 185 of the 3.0 M solution with water until a new volume of 750 is obtained. Calculate the new concentration
svlad2 [7]

Answer:

0.74M

Explanation:

Step 1 :

Data obtained from the question.

Initial concentration (C1) = 3M

Initial volume (V2) = 185mL

Final volume (V2) = 750mL

Final concentration (C2) =..?

Step 2:

Determination of the new concentration of the solution.

The new concentration of the solution can be obtained by using the dilution formula as shown below:

C1V1 = C2V2

3 x 185 = C2 x 750

Divide both side by 750

C2 = 3 x 185 / 750

C2 = 0.74M

Therefore, the new concentration of the solution is 0.74M

7 0
3 years ago
Which of the following would form a cation? Ne Li O I
geniusboy [140]
Li because its charge is +1.
5 0
3 years ago
Read 2 more answers
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