Answer:
![\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%3D%28a%5E%7B2%7D%2Bb%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Step-by-step explanation:
∵∛x = (x)^1/3
∴ ![\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%3D%28a%5E%7B2%7D%2Bb%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
So you can replace the radicals by fractional exponents
Step 1 , switch sides - 29-3b<10
step 2 , subtract 29 from both sides - -3b< -19
step 3 , multiply both sides by -1 - 3b > 19
step 4 (answer) - divide by 3 = 19/3
110 because when you basically spend most of your time in math you become a math genius and then you whole family is proud of you thank you
Hope this helps let me know if it does :)
Step-by-step explanation:
By Intersecting Chords Theorem,
9 * 4x = 8 * (4x + 2).
=> 36x = 32x + 16
=> 4x = 16, x = 4. (2)