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sattari [20]
3 years ago
12

Which expressions are equivalent to the one below?

Mathematics
1 answer:
den301095 [7]3 years ago
8 0
The expressions that show different ways to rewrite
\dfrac{16^{x}}{4^{x}}

are ...
  a. (4^x * 4^x) / 4^x
  b. 4^x
  c. (16 / 4)^x
You might be interested in
95 points <br><br> Simplify (4^9/4^3)^5 Show your work for full credit
dexar [7]

Answer:

  • 4^{30}

Step-by-step explanation:

  • (4^9/4^3)^5=
  • (4^{9-3})^5=
  • (4^6)^5=
  • 4^{6*5}=
  • 4^{30}
3 0
2 years ago
Read 2 more answers
A bag contains 8 red marbles, 7 blue marbles, and 6 green marbles. Adam randomly picks out a marble from a bag. What is the theo
alexandr1967 [171]

Answer:

⅓

Step-by-step explanation:

8+7+6

total= 21

blue= 7÷21

1/3

7 0
3 years ago
Read 2 more answers
First let’s go on a trip! you come into some money and decide to go to canada where the exchange rate is 1.04 canadian dollars t
Ksenya-84 [330]
13092.50 Canadian dollars equals to $10000 US dollars.
6 0
3 years ago
What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1
Nuetrik [128]

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

3 0
3 years ago
Complete the table of values for this absolute value function. Then use the drawing tool(s) to graph the function. F(x)-2|x+1|-1
rusak2 [61]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the equation

f\left(x\right)=-2|x+1|-1

As some of the absolute rules are:

  • \left|a\right|=a,\:a\ge 0
  • \:|-a|=a,\:\quad \:a>0

NOW, let us solve!

Let us substitute all the table values

Putting x = -4

y=-2\left|-4+1\right|-1        ∵\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0

y=-6-1

y=-7

So, when x = -4, then y = -7

Putting x = -3

y=-2|-3+1|-1\:

y=-4-1

y=-5

when x = -3, then y = -5

Putting x = -2

y=-2\left|-2+1\right|-1

y=-2-1

y=-3

when x = -2, then y = -3

Putting x = -1

y=-2\left|-1+1\right|-1

y=-0-1

y=-1

when x = -1, then y = -1

Putting x = 0

y=-2\left|0+1\right|-1

y=-2-1

y=-3

when x = 0, then y = -3

Putting x = 1

y=-2\left|1+1\right|-1

y=-4-1

y=-5

when x = 1, then y = -5

The graph is also attached below.

6 0
3 years ago
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