The sum of the geometric series is 2199; option E.
- The 36th term of the arithmetic series is -60.5 option C
- The sum of the arithmetic series is 2547; option E
- The missing geometric sequence are; 1.614375, 3.30946875, 6.7844109375. option E
<h3>Arithmetic and Geometric series</h3>
S6 = a(rⁿ - 1) / r -1
= 1468(1/3^6 - 1) / (1/3 - 1)
= 1468(0.00137174211248 - 1) / -2/3
= 1468(-0.9986282578875) / -0.66666666666666
= -1,465.98628257885 / -0.66666666666666
= 2198.97942386829
Approximately,
S6 = 2199
Arithmetic series
Sn = n/2{2a + (n -1)d}
= 36/2 {2×27 + (36-1)-5/2}
= 18{54 + (35)-5/2}
= 18(54 + 175/2)
= 18(54 + 87.5)
= 18(141.5)
s36 = 2547
a36 = a + (n - 1) d
= 27 + (36 - 1)-5/2
= 27 + (35)-5/2
=27 + -175/2
= 27 - 87.5
= -60.5
S20 = n/2{2a + (n -1)d}
= 20/2{2×27 + (20-1)-5}
= 10(54 + (19)-5)
= 10{54 + (-95)}
= 10(54-95)
= 10(-41)
s20 = -410
Missing terms of the geometric sequence:
nth term = ar^n-1
448/135 = 63/80×r^(6-1)
448/135 = 63/80×r^5
r^5 = 448/135 ÷ 63/80
= 448/135 × 80/63
= 35,840/8,505
r = 5√35,840/5√8505
= 946.57/461.11
r = 2.05
Second term = a×r
= 63/80×2.05
= 1.614375
Third term = ar²
= 63/80×2.05²
= 63/80×4.2025
= 3.30946875
Fourth term = 63/80 × 2.05³
= 63/80×8.615125
= 6.7844109375
Therefore, none of these are correct
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Answer:
The answer 2400.
Step-by-step explanation:
2×10^3=2×1000=2000
4×10^2=4×100=400
2000+400=2400
Answer:
B (300, 400)
Step-by-step explanation:
The profit maximization will be when the sum of the products will be greater. The maximum profit will be when x is 300 and y is 400. If we put in the equation :
P = 40x + 55 y
A - When x = 0 , y = 500
P = [40 * 0] + [55 * 500]
P = 27500
B -
When x = 300 , y = 400
P = [40 * 300] + [55 * 400]
P = 34000
C -
When x = 380 , y = 200
P = [40 * 380] + [55 * 200]
P = 26200
D -
When x = 400 , y = 0
P = [40 * 400] + [55 * 400]
P = 16000
Answer:

Step-by-step explanation:
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