Using the feasible region below, determine which x and y values will maximize the profit, P, in the equation P = 40x + 55y * 1 p oint A(0, 500)
B(300, 400)
C(380, 200)
D(400, 0)
E None of the Above
1 answer:
Answer:
B (300, 400)
Step-by-step explanation:
The profit maximization will be when the sum of the products will be greater. The maximum profit will be when x is 300 and y is 400. If we put in the equation :
P = 40x + 55 y
A - When x = 0 , y = 500
P = [40 * 0] + [55 * 500]
P = 27500
B -
When x = 300 , y = 400
P = [40 * 300] + [55 * 400]
P = 34000
C -
When x = 380 , y = 200
P = [40 * 380] + [55 * 200]
P = 26200
D -
When x = 400 , y = 0
P = [40 * 400] + [55 * 400]
P = 16000
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