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2 years ago

What is the square roooot of 4

Mathematics

1 answer:

mrs_skeptik [129]2 years ago

5 0

The answer to this question is .....square root of 4 is ...2 because 2*2 is 4

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73 * 10 to the power of 2

Verdich [7]

73(10)^2

730^2

answer: 532,900

7 0

2 years ago

Which value of "b" will make the trinomial 4x^2 + bx + 36 a perfect square trinomial? 0 24 O 6 O 12 O 4

Lena [83]

Answer:

Step-by-step explanation:

Reverse solve for a perfect Square

(b/2a)^2=36

(b/2(4))^2=36

(b/8)^2=36

b/8=6

b=48

48 makes the trinomial a perfect square trinomial.

4 0

2 years ago

Free points over here<br><br> 20+20=

zvonat [6]

Answer:

9348283848384848383838482

7 0

3 years ago

Read 2 more answers

What is "k" ? 20k+4+33k-9

kifflom [539]

I think it is -45
Hope this helps

7 0

3 years ago

Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$

Therefore, we get

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98$

So, the sample standard deviation is 6.98.

3 0

2 years ago